- #1

Shackleford

- 1,661

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Member warned about not using the homework template

I don't recall ever doing this but maybe I have.

z

p = √6

Ψ = π/4

Using the formula in the notes, z = 6

z

^{2}= a = p [cos Ψ + i sin Ψ] = √3 + i*√3p = √6

Ψ = π/4

Using the formula in the notes, z = 6

^{1/4}* exp[i*(π/4 + 2π*k)/2], k = 0, 1.
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