MHB Find the Volume of Rotated Shaded Region Bounded by y=x^2+1, y=5, and y-axis

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The discussion focuses on finding the volume of the solid formed by rotating the shaded region bounded by the parabola y = x^2 + 1, the line y = 5, and the y-axis around the y-axis. The volume can be calculated using the disk method, leading to the integral V = π∫(1 to 5)(y - 1) dy. Alternatively, the shell method is applied, resulting in the integral V = 2π∫(0 to 2)(4x - x^3) dx. Both methods provide a way to compute the volume of the solid generated by the rotation of the specified region. The discussion emphasizes the application of integration techniques in calculating volumes of solids of revolution.
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In the diagram, the shaded region is bounded by the parabola y = x2 + 1, the y-axis and the line y = 5.
Find the volume of the solid formed when the shaded region is rotated about the y-axis.
Got no diagram but limits will be 2-0 coz its on right side
 
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Using the first quadrant area, and the disk method, we may state:

$\displaystyle dV=\pi x^2\,dy$

Since we have $\displaystyle x^2=y-1$ we may state:

$\displaystyle dV=\pi(y-1)\,dy$

And by integration, we have:

$\displaystyle V=\pi\int_1^5 y-1\,dy$

Using the shell method, we find:

$\displaystyle dV=2\pi x(5-y)\,dx$

Since $\displaystyle y=x^2+1$, we may state:

$\displaystyle dV=2\pi x(5-(x^2+1))\,dx=2\pi(4x-x^3)\,dx$

And by integration, we have:

$\displaystyle V=2\pi\int_0^2 4x-x^3\,dx$
 
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