Find the Volume of Rotated Shaded Region Bounded by y=x^2+1, y=5, and y-axis

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SUMMARY

The volume of the solid formed by rotating the shaded region bounded by the parabola y = x² + 1, the line y = 5, and the y-axis is calculated using both the disk and shell methods. The disk method yields the volume as V = π∫₁⁵ (y - 1) dy, while the shell method results in V = 2π∫₀² (4x - x³) dx. Both methods confirm the same volume for the solid of revolution, demonstrating the consistency of calculus techniques in solving such problems.

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  • Knowledge of the properties of parabolas and their equations.
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In the diagram, the shaded region is bounded by the parabola y = x2 + 1, the y-axis and the line y = 5.
Find the volume of the solid formed when the shaded region is rotated about the y-axis.
Got no diagram but limits will be 2-0 coz its on right side
 
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Using the first quadrant area, and the disk method, we may state:

$\displaystyle dV=\pi x^2\,dy$

Since we have $\displaystyle x^2=y-1$ we may state:

$\displaystyle dV=\pi(y-1)\,dy$

And by integration, we have:

$\displaystyle V=\pi\int_1^5 y-1\,dy$

Using the shell method, we find:

$\displaystyle dV=2\pi x(5-y)\,dx$

Since $\displaystyle y=x^2+1$, we may state:

$\displaystyle dV=2\pi x(5-(x^2+1))\,dx=2\pi(4x-x^3)\,dx$

And by integration, we have:

$\displaystyle V=2\pi\int_0^2 4x-x^3\,dx$
 

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