- #1

utkarshakash

Gold Member

- 855

- 13

## Homework Statement

If [itex] \displaystyle \int_0^1 \dfrac{e^t}{t+1} dt = a[/itex] then [itex]\displaystyle \int_{b-1}^b \dfrac{e^{-t}}{t-b-1} dt [/itex] is equal to

## Homework Equations

## The Attempt at a Solution

I used the definite integral property in the second integral

[itex]\displaystyle \int_{b-1}^b \dfrac{e^{-2b-1-t}}{b-2-t} dt [/itex]