Find Unit Vector perpendicular to the Surface,(adsbygoogle = window.adsbygoogle || []).push({});

x^{3}+zx=1 at the point P=(1,2,-1)

I figures that the perpendicular vector would be,

N(X)=grad(x^{3}+zx)

= (3x^{2}+z, 0, x)

N(P)= (3,0,1)

Then the unit vector would be,

n=N(P)/||N(P)||

n=(3/5^{1/2},0,1/5^{1/2})

The answer i get is not the right answer and i dont see where im going wrong.

Thanks,

**Physics Forums - The Fusion of Science and Community**

# Find Unit Vector perpendicular to the Surface

Know someone interested in this topic? Share a link to this question via email,
Google+,
Twitter, or
Facebook

- Similar discussions for: Find Unit Vector perpendicular to the Surface

Loading...

**Physics Forums - The Fusion of Science and Community**