Find Values of "a" for No Critical Number | Function "f" Homework

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SUMMARY

The discussion focuses on determining the values of the constant "a" for which the function "f" has no critical numbers. It is established that critical points occur when the derivative f'(x) = -2(a^2 + a - 6)sin(2x) + a - 2 is either undefined or equal to zero. The critical points are absent when the condition sin(2x) = (a - 2) / (-2(a^2 + a - 2)) exceeds 1. This leads to the conclusion that specific values of "a" must be avoided to ensure no critical points exist.

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Homework Statement



Determine the values of the number "a" for which the function "f" has no critical number.

Homework Equations


If I'm not mistaken, this should be the result for differentiation:

The Attempt at a Solution



Critical points are either where function derivation is not defined (does not exists), OR where the derivation is equal to zero.
This is my answer; although, it seems to be a very complicated and somehow incorrect:"a" should not be these values, so "f" will not have any critical number.
 
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No, a is a constant not function of x!

As you say, a "critical point" is one where [itex]f'(x)= -2(a^2+a- 6)sin(2x)+ a- 2[/itex] does not exist or is 0. That exists for all a and is 0 when
[tex]-2(a^2+ a- 6)sin(2x)+ a- 2= 0[/itex]<br /> so<br /> [tex]sin(2x)= \frac{a-2}{-2(a^2+ + a- 2)}[/itex]<br /> That never happens if <br /> [tex]\frac{a-2}{-2(a^2+ a- 2)}> 1[/itex][/tex][/tex][/tex]
 

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