Find Voltage: How to Solve for V_1 and V_2 using Mesh Current Method

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Discussion Overview

The discussion revolves around solving for voltages V_1 and V_2 in a circuit using the mesh current method, specifically through the application of supermesh analysis. Participants are exploring the calculations and relationships between current and voltage in the context of circuit analysis.

Discussion Character

  • Homework-related
  • Mathematical reasoning
  • Technical explanation
  • Debate/contested

Main Points Raised

  • The initial equations for mesh currents I1 and I2 are presented, with calculations leading to I1 = 3.10 A and I2 = 2 A.
  • V_1 is calculated using the formula V = IR, resulting in V_1 = 88 V based on the current difference of 1.1 A across an 80-ohm resistor.
  • The participant expresses uncertainty about calculating V_2, initially proposing to use the power equations and KVL.
  • Another participant points out that V_2 is the voltage across the current source and suggests considering other elements in parallel with the current source.
  • There is a clarification regarding the resistor in parallel with the current source, with a focus on the 4-ohm resistor and its relationship to the current source's voltage.
  • It is noted that the voltage across the parallel resistor is the same as that across the current source, leading to a potential calculation for V_2 based on the current through that resistor.

Areas of Agreement / Disagreement

Participants express differing views on the calculation of V_2, with some uncertainty about the elements involved and the correct approach to take. The discussion remains unresolved regarding the exact value of V_2 and the methods used to derive it.

Contextual Notes

There are limitations in the clarity of the circuit elements and their configurations, which may affect the calculations. The assumptions regarding the relationships between voltage and current in parallel components are also not fully resolved.

Who May Find This Useful

This discussion may be useful for students and practitioners interested in circuit analysis, particularly those learning about mesh current methods and the implications of circuit components in parallel.

Heat
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Homework Statement


Hi I'm trying to solve the following using mesh current method, instead of node voltage.

For this I decided to use supermesh.

I made loop 1 the leftmost loop, and loop 2 combination of the center and right loop.

-150 + 20I1 + 80(I1-I2) = 0
40I2 = 4I2 = 80 (I2-I1) = 0

solving for this gives:

I1 = 3.10 A
I2 = 2 AI'm supposed to find v_1 and v_2. So since to find v_1, I do the following

3.10 - 2 = 1.1
V=IR = (1.1 A)(80 ohms) = 88 V <--------seems about right.

So now I'm trying to find v_2.

The only equations, I'm familiar is p = vi , p = i^2R v = ir. and since the current is given of 11.25 A for that portion.
V_2 = (11.25)(R)

I don't know how to proceed. I'm thinking about applying KVL, since voltage across a loop is 0.

which would be on second loop

-80(1.1 A)+40(2 A) + v_2 = 0
v_2 = 8 V <-----------I'm not sure if this is right, or if anything I did is right. :(

Circuit: http://imgur.com/LLno5.jpg
 

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V2 is the voltage across the current source. Ask yourself if there are other elements in the circuit that must also have the same drop in potential across them. In other words, are there elements connected in parallel with the current source? Hope that helps :)
 
I'm not sure I understand. I see that the 5ohm resistor is in parallel to the 3 A current source.
 
I'm guessing you meant the 4ohm resistor and not 5ohm since I don't see one in the circuit. The resistor in parallel with the current source has the same voltage across it as the current source. So if you know the current through that resistor, you can calculate the voltage drop (v=ir), which is the same voltage as V2.
 

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