1. The problem statement, all variables and given/known data Consider the circuit in the figure and calculate V1, V2 and IA. Notice that the symbols V and A represent, respectively, an ideal voltmeter and an ideal ammeter. 2. Relevant equations Ohm's Law $$V=RI$$ KVL The sum of the voltages of a mesh in a circuit equals zero. We apply a positive sign to the voltages following the direction of the mesh and a negative sign otherwise. 3. The attempt at a solution So first because we are in the presence of an ideal voltmeter (zero internal resistance) and an ideal ammeter (infinite internal resistance), I switched them with an open circuit and a short circuit, respectively. Then I applied the KVL to the only mesh in the circuit and obtained: $$V_2 + V_1 + 15V =0$$ Because $$V_1 = 10 \Omega \times I_A$$ and $$V_2= 5 \Omega \times I_A$$ Substituting in the first equation we get to $$I_A=-1A$$. Substituting the found current in the other two equations we get to $$V_1 = -10 V$$ and $$V_2= -5 V$$. However the exercise solution gives me the same results but with the positive sign. What have I done wrong? Note: I used passive convention in all components. Thanks!