Find volume using disk/washer/shell method

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Homework Help Overview

The discussion revolves around finding the volume of a solid generated by revolving a region bounded by the equations y=x, y=0, y=4, and the line x=5 about the line x=5. The original poster is considering using the washer method for this calculation.

Discussion Character

  • Exploratory, Assumption checking

Approaches and Questions Raised

  • Participants discuss the washer method and the need to identify the outer and inner radii for the volume calculation. There are questions about the reasoning behind the values of R and r, particularly why r is considered to be zero.

Discussion Status

Participants have engaged in clarifying the definitions of the radii involved in the washer method. Some have provided insights into the geometric interpretation of the problem, and there appears to be a productive exchange regarding the understanding of the radii calculations.

Contextual Notes

There is mention of a sketch of the region being revolved, which may aid in visualizing the problem. The discussion includes references to textbook definitions and interpretations of the radii.

kari82
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Find volume of the solid generated revolving the region bounded by the graphs of the equations about line x=5

y=x, y=0, y=4, x=5

My plan is to use washer method. V=pi∫R(y)^2-r(y)^2 dy from y=0 and y=4

Im having trouble finding the equations for R and r. Can someone please explain me what would be a way to find those equations? Thanks!
 
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kari82 said:
Find volume of the solid generated revolving the region bounded by the graphs of the equations about line x=5

y=x, y=0, y=4, x=5

My plan is to use washer method. V=pi∫R(y)^2-r(y)^2 dy from y=0 and y=4

Im having trouble finding the equations for R and r. Can someone please explain me what would be a way to find those equations? Thanks!

Have you drawn a sketch of the region being revolved? The typical area element is a trapezoid whose left edge is along the line y = x and whose right edge is along the line x = 5.
 
yes, i did... and the book says that R=5-y and r=0.. but I can't see why r=0..
 
I think I got it.. r=0 because when it rotates along x=5 there is no inner radius?
 
Both radii are calculated as distances from the line x = 5. The large radius, R, is 5 - y. The small radius is 5 - 5 = 0. IOW, all of the disks have a radius of 5 - y. Does that make sense?
 
Yes! Thank you so much!
 

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