Find Zeros of f(x): Solving Functions Problem Homework

  • Thread starter Thread starter luludatis
  • Start date Start date
  • Tags Tags
    Functions
Click For Summary

Homework Help Overview

The discussion revolves around finding the zeros of the cubic function f(x)=4x³-2x²-8x+2. The original poster expresses uncertainty about their approach to identifying the zeros, having used a calculator to test rational roots.

Discussion Character

  • Exploratory, Assumption checking

Approaches and Questions Raised

  • The original poster attempts to find zeros by testing rational roots using a calculator, questioning whether this is an acceptable method. Other participants suggest alternative methods, such as the cubic formula and numerical methods like Newton's or bisection method.

Discussion Status

The discussion is ongoing, with participants exploring different methods for finding zeros. Some guidance has been offered regarding alternative approaches, but there is no explicit consensus on the preferred method.

Contextual Notes

The original poster notes that they have not been taught the cubic formula, which may limit their approach to solving the problem. There is also an indication of reliance on calculators for finding solutions.

luludatis
Messages
6
Reaction score
0

Homework Statement


For the function f(x)=4x3-2x2-8x+2, the slope at any point on f(x) can be calculated using the equation m(x)=12x2-4x-8

Weirdly enough, I was able to answer all other 5 questions about this, except for the basics:

What are the zeroes of f(x)

Homework Equations


rational zeroes: +-p/q

The Attempt at a Solution


tried every possible rational zero. I just plugged it into the calculator and it gives me an answer, but I'm not sure if that is what we are supposed to do. I'm just trying to corroborate if there is not another way of solving it.
 
Physics news on Phys.org
You could always use the cubic formula, but that's a beast.
 
never used it, she did not teach it to us, so calculator it is :] thank you!
 
Do you know Newton's or bisection method?
 
i don't think so...
 

Similar threads

Replies
8
Views
4K
  • · Replies 13 ·
Replies
13
Views
3K
Replies
9
Views
2K
  • · Replies 11 ·
Replies
11
Views
3K
  • · Replies 14 ·
Replies
14
Views
4K
  • · Replies 7 ·
Replies
7
Views
4K
Replies
20
Views
3K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 10 ·
Replies
10
Views
5K
  • · Replies 11 ·
Replies
11
Views
3K