Finding a Vector in Cartesian form

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To find the vector u→ in Cartesian form, given that it is in the first quadrant with a magnitude of 8 and a direction of 75°, the coordinates can be calculated using trigonometric functions. The x-coordinate is found using the cosine of the angle, and the y-coordinate using the sine, resulting in approximately (2.1, 7.7) when rounded to one decimal place. The discussion highlights confusion stemming from an incorrect assertion made by a library patron, emphasizing the importance of verifying mathematical solutions. The original poster seeks reassurance from the forum community, indicating a desire for clarity and confirmation of their calculations. Engaging with knowledgeable sources can help resolve uncertainties in mathematical problems.
Physics345
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Homework Statement


Find u→ in Cartesian form if u→ is a vector in the first quadrant, ∣u→∣=8 and the direction of u→ is 75° in standard position. Round each of the coordinates to one decimal place.

Homework Equations


none

The Attempt at a Solution


I'm certain this is correct, but some guy at the library told me it was wrong, can someone please confirm if it is wrong for me.
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Physics345 said:
but some guy at the library told me it was wrong
Now you can say that some guy on the internet said it was right.

If the guy in the library didn't tell you why it was wrong, he wasn't of much help...
 
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DrClaude said:
Now you can say that some guy on the internet said it was right.

If the guy ion the library didn't tell you why it was wrong, he wasn't of much help...

He had an explanation I just couldn't understand it, I guess he just wanted to talk. I assumed he was correct since he was an older man he wouldn't bother making it up. I guess I should have known a most of the people in that library are either homeless or on drugs, no wondering it's being shut down. Anyways I thought I would double check and make sure I'm not missing something by asking the knowledgeable and wonderful people on here! Better safe than sorry. Thanks a lot Dr. Claude.
 

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