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## Homework Statement

Find a vector-valued function

**f**that parametrizes the curve (x-1)^2 + y^2 = 1

## Homework Equations

(x-1)^2 + y^2 = 1

## The Attempt at a Solution

The equation is the graph of a circle that is 1 unit to the right of the origin, therefore a parametrization would be

x(t) = cos(t) + 1

y(t) = sin(t)

Therefore a vector-valued function that parametrizes this curve is given by

**r**(t) = (cos(t) + 1)

**i**+ sin(t)

**j**I've been having trouble with parametrization lately so I was wondering if this is correct.

**Is it entirely visual and you just have to have a "feel" for it?**

*Also, is there a better method to go about this sort of thing?*