Finding Acceleration of Two blocks connected by a string.

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Two blocks of different materials connected by a string slide down an inclined plane, with varying coefficients of friction. In Part A, the correct formula for the acceleration of block A, when μA < μB, is derived as aA, 1= (mAgsinθ+mBgsinθ-AmAgcosθ-μBgcosθ)/(mA+mB). In Part B, the acceleration formula changes when μA > μB, leading to a misunderstanding where the user incorrectly assumed both blocks would have the same acceleration. The correct formula for Part B is aA, 2= g(sinθ- μAcosθ), highlighting the importance of recognizing that the blocks may not touch or share the same acceleration under different friction conditions. The discussion emphasizes the need to carefully analyze the effects of friction on the system's dynamics.
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1. Two blocks made of different materials connected together by a thin cord, slide down a plane ramp inclined at an angle θ to the horizontal. The masses of the blocks are mA and mB and the coefficients of friction are μA and μB.

GIANCOLI.ch05.p021.jpg

PART A
If μA < μB, determine a formula for the acceleration of block A in terms of mA, mB, and θ.
PART B
If μA > μB, determine a formula for the acceleration of block A in terms of mA, mB, and θ.


3. I got Part A right, of which aA, 1= (mAgsinθ+mBgsinθ-AmAgcosθ-μBgcosθ)/(mA+mB)

For Part B, I attempted it to solve it, and got the same answer as I did in Part A, yet MasteringPhysics says this is incorrect. Am I doing anything wrong? "The correct answer does not depend on the variables: mA, mB, or μB. "

Thanks for the help in advance.

 
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Hint: Do the blocks have the same acceleration?
 
Oh, got it. I simply assumed that if μAB, then the blocks would end up touching each other and have the same acceleration;

I see now that's not the case. I got aA, 2= g(sinθ- μAcosθ). Thanks for your quick response and help, Doc Al!
 
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