Finding an Indeterminate Limit with L'Hôpital's Rule: Help and Explanation

  • Thread starter Thread starter swampwiz
  • Start date Start date
  • Tags Tags
    Limit
swampwiz
Messages
567
Reaction score
83
I can't seem to figure out how to find this seemingly simple limit (that is shown numerically to go to 0)

lim x → ∞ ( x rx )

for r < 1

This is an indeterminate form of ∞ * 0, but when I try to apply L'Hôpital's rule as

lim x → ∞ ( rx / ( 1 / x ) )

I end up getting an expression of the form x2 rx, with further application of the rule generating higher and higher powers of x

I'm totally stuck!
 
Physics news on Phys.org
You have the right idea. Try this instead:

lim x → ∞ (x/(1/r)x)
 
gb7nash said:
You have the right idea. Try this instead:

lim x → ∞ (x/(1/r)x)

But wouldn't that be ∞ / ∞ ? L'Hopital's rule only applies to 0 / 0
 
swampwiz said:
L'Hopital's rule only applies to 0 / 0

No it doesn't. It also applies to +- inf/inf
 

Similar threads

Back
Top