# Finding center of gravity

1. Sep 15, 2011

### mbud

1. The problem statement, all variables and given/known data

<a href="http://www.flickr.com/photos/56362284@N04/6149231787/" [Broken] title="untitled by redmond0991, on Flickr"><img src="http://farm7.static.flickr.com/6065/6149231787_e6230d69ab.jpg" width="407" height="229" alt="untitled"></a>

http://www.flickr.com/photos/56362284@N04/6149231787/

Ballast of mass Mb kg per meter length is added to an empty barge of mass M. The weight of the ballast acts at point A (on the barge centerline at the bottom of the hull) and is uniformly distributed along the length of the barge. The addition of the ballast will shift the center of gravity from G to G'

Write out an expression for the height of the new center of gravity above the bottom of the hull in terms of Mb (distance AG' ) using moments.

2. Relevant equations

using moments

3. The attempt at a solution

I'm not sure where to take the moment from, from the base or from G=0,

let dist AG' = x

If i take it from G, i get, 2Mb+(2-x)M = 0, is that right?

Last edited by a moderator: May 5, 2017