Finding Centre of Gravity | Calculating Moments and Work Done

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Homework Help Overview

The discussion revolves around finding the center of gravity of an irregularly shaped object and analyzing forces and moments acting on a tray held horizontally by a waiter. The problem includes calculating forces exerted at specific points and determining work done against gravity.

Discussion Character

  • Mixed

Approaches and Questions Raised

  • Participants explore methods to find the center of gravity experimentally and discuss the implications of moving a drink along the tray on the forces involved.
  • Some participants question the correctness of dimensions in the provided diagram and the calculations related to torques and forces.
  • There is an inquiry about the relationship between the forces exerted by the waiter and the total weight supported by the tray.

Discussion Status

Participants are actively engaging with the problem, raising questions about the calculations and assumptions made. Some guidance is offered regarding the need to consider the weight of the tray and the glass of water in the analysis of forces. There is no explicit consensus on the correctness of the answers provided, and further clarification is sought.

Contextual Notes

Participants note potential discrepancies in the diagram's dimensions and emphasize the importance of correctly identifying the center of gravity for the irregular shape. The discussion also highlights the need to account for all forces and moments in static equilibrium conditions.

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Homework Statement


1.Describe how you would find the centre of gravity of a piece of cardboard of irregular shape.

2.The figure represents a tray held horizontally by a glass of water. The tary has a weight of 6N amd supports a drink of weight 3N.The waiter provides a force at P. The tray may pivot about T.(THE DRAWING IS ATTACHED)

(i)Use the information to find the force provided by the waiter at P and the upward force the hand exerts at T.
(ii)The drink is moved along the tray closer to the hand.Is the force needed to keep the tary horizontal now less, greater or the same? Explain your answer.
(iii)How much work is done by the waiter in lifting the tray and drink through a geight of 0.6m?


Homework Equations


Moments=Force X Distance
M=Fd

Work Done=Force X Distance
W=Fd


The Attempt at a Solution



2(i) 40cm X 3N=5cm X PN
120=5P
120/5=P
24=P
(ii)The force is not less (BUT I CAN'T EXPLAIN WHY):confused:
(iii)Work Done=0.6 X 6N=3.6J
 

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(ii)The force is not less (BUT I CAN'T EXPLAIN WHY)

There is the mass of the tray and the mass of the glass of water. The total mass (and therefore weight) does not change.

When working with static forces and moments, one looks at net force = 0, and net moment = 0.

The change in moment arm changes the distribution of force, but opposing net forces must add to zero.
 
The dimensions don't add correctly on your diagram; is the water glass 25 cm from the pivot and is the tray length 40 cm?? Once this is corrected, sum torques about the pivot as you have done, but don't forget to include the torque of the tray weight about the pivot point. You'll need to do a little math to calculate the lever arn length from the tray's center of gravity. And show how to determine the force T. And which force do you use when determining the work done by the waiter in lifting the tray?
 
So are my other answers correct? And do you know how would i find the centre of gravity for the irregular shaped piece of cardboard?
 
crpcrpcrp said:
So are my other answers correct? And do you know how would i find the centre of gravity for the irregular shaped piece of cardboard?
For the irregular shape, I assume you are trying to find the c.g. experimentally. What is the definition of center of gravity?

For problem 2(i), assuming you have corrected your equation to solve for P, the downward force of the waiter's thumb on the tray, you have not yet shown your attempt to calculate T, the upward force exerted by his fingers.
For (ii), as pointed out, the P and T forces will change, but their sum will not.

For part(iii), the work done by the waiter is the work done against gravity. What is the work done by gravity? Your answer is not correct. Alternatively, you could sum the work done by P and T and get the same result. Show your attempt, please.
 

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