- #1

Shelnutt2

- 57

- 0

Cl- 6250 mg/L or 176 mmol/L

SO4^2- 6250 mg/L or 65 mmol/L

Na+ 6250 mg/L or 272 mmol/L

K+ 6250 mg/L or 160 mmol/L

Ca^2+ 5000 mg/L or 125 mmol/L

If I'm doing my math right, that means my solution (including the water) is 56.304 mol/L correct?

So if that is 56.304 mol/liter then I just multiple by 1000 L / m^3 to get 56,304 mol / m^3 correct?

Now with this 56,304 mol / m^3, I can multiple by the Faraday Constant (9.65 x 10^4 C / mol) to get (9.65 x 10^4) * 56,304 = 5,433,336,000 C / m^3 correct?

Then I can use the equation of I = delta Q / delta A = n * v * A . Now v * A = flow, and my flow is .00657 m^3/s

So it's just I = 5,433,336,000 * .00657 = 35,697,017.52 amps? That seems very very wrong (it's very high).

Now one thing I found said it's I = q * n *v * A, where q is charge, n is charge density, v is velocity and A is area. That doesn't make sense to me though because q is in Coulombs, n is C / m^3, v is m/s and A is m^2, so when multiplied you'd get I (amps) = c^2 / s. So I'm pretty sure it's just n * v * A, but man that is a lot of amps.

Thanks