Finding Charge of Two Charged Spheres

AI Thread Summary
To find the charge on two charged spheres that hang at equilibrium, consider both gravitational and electrostatic forces acting on them. Each sphere has a mass of 15.1 g and is charged such that one has twice the charge of the other. The spheres hang at an angle of 10.3° with the vertical, indicating a balance between the gravitational force and the electrostatic repulsion. The problem requires applying the principles of equilibrium and the relationship between charge, electric field, and force. Understanding these forces is crucial for calculating the charge on each sphere.
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Homework Statement



Two hard rubber spheres, each of mass m = 15.1 g, are rubbed with fur on a dry day and are then suspended with two insulating strings of length L = 4.90 cm whose support points are a distance d = 2.97 cm from each other as shown in the figure below. During the rubbing process, one sphere receives exactly twice the charge of the other. They are observed to hang at equilibrium, each at an angle of θ = 10.3° with the vertical. Find the amount of charge on each sphere.

[PLAIN]http://img269.imageshack.us/img269/4021/44539563.jpg

Homework Equations





The Attempt at a Solution



I'm not sure how to approach this problem. If the charged particles are in a uniform Electric Field then

\vec{F} = q \vec{E} = m \vec{a}

\vec{a} = \frac{q \vec{E}}{m}

The problem says "hang at equilibrium", if this means they're not moving then the acceleration of the particles is 0. If it means electrostatic equiblirium, then the we know the electric field is 0 everywhere. So what could we do? How should one appraoch this problem? :confused:
 
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dont forget about gravity

it is both the force of gravity and electrostatics that allows them to keep this equilibrium.

lackos
 
lackos said:
dont forget about gravity

it is both the force of gravity and electrostatics that allows them to keep this equilibrium.

lackos

I don't understand, how could I use this to find the charge on each sphere?
 
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