Find d(adsbygoogle = window.adsbygoogle || []).push({}); ^{2}y/dx^{2}as a function of t if x = t - t^{2}and y = t - t^{3}

Ok, so this basically means we're going to take the second derivative of y with respect to t over the derivative of x with respect to t.

So the second derivative of y would be.

[2 - 6t + 6t^{2}]/(1 - 2t)^{2}

Now, we just put that over the first derivative of x which is 1 - 2t so we get:

[[2 - 6t + 6t^{2}]/(1 - 2t)^{2}]/(1 - 2t)

=

(2 - 6t + 6t^{2})/(1 - 2t)^{3}

Correct or incorrect?

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# Homework Help: Finding d^2y/dx^2 for a parametrized curve

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