- #1

- 217

- 1

^{2}y/dx

^{2}as a function of t if x = t - t

^{2}and y = t - t

^{3}

Ok, so this basically means we're going to take the second derivative of y with respect to t over the derivative of x with respect to t.

So the second derivative of y would be.

[2 - 6t + 6t

^{2}]/(1 - 2t)

^{2}

Now, we just put that over the first derivative of x which is 1 - 2t so we get:

[[2 - 6t + 6t

^{2}]/(1 - 2t)

^{2}]/(1 - 2t)

=

(2 - 6t + 6t

^{2})/(1 - 2t)

^{3}

Correct or incorrect?