Jul 10, 2015 #1 scottshannon Messages 46 Reaction score 0 I am trying to find the derivative of x^x using the limit definition and am unable to follow what I have read. Can someone help me understand why lim [(x+h)^h -1]/h as h ---> 0 = ln(x). This part of the derivatio Attachments 11143198_952395444799534_6323303759743605136_n.jpg 27.2 KB · Views: 5,421
I am trying to find the derivative of x^x using the limit definition and am unable to follow what I have read. Can someone help me understand why lim [(x+h)^h -1]/h as h ---> 0 = ln(x). This part of the derivatio
Jul 17, 2015 #3 Qwertywerty Messages 501 Reaction score 66 Limit (a∧h) = 1 + h×log(a)/1! + ((h×log(a))∧2)/2! + ... h→0 For the steps performed on the right side , use , as already said , x = e∧log(x) , and Limit (log(1+h)) = h - (h∧2)/2 + (h∧3)/3 - ... h→0 *Log is taken to base e .
Limit (a∧h) = 1 + h×log(a)/1! + ((h×log(a))∧2)/2! + ... h→0 For the steps performed on the right side , use , as already said , x = e∧log(x) , and Limit (log(1+h)) = h - (h∧2)/2 + (h∧3)/3 - ... h→0 *Log is taken to base e .