(adsbygoogle = window.adsbygoogle || []).push({}); 1. The problem statement, all variables and given/known data

A box of massmwith an initial velocity ofvslides down a plane, inclined at_{0}θwith respect to the horizontal. The coefficient of kinetic friction isμ. The box stops after sliding a distancex. How much work is done by friction?

2. Relevant equations

Work=Force*x*cosθ

W=ΔKE

KE_{0}=(.5)(m)(v_{0}^{2})

3. The attempt at a solution

F_{F}=(μ)(F_{N})

F_{Nety}=F_{N}-F_{gy}

0=F_{N}-F_{gy}

F_{N}=F_{gy}

F_{gy}=mgcosθ

F_{FK}=(μ)(F_{N})

F_{FK}=(μ)(mgcosθ)

Work=Force*x*cosθ

Work=(μ)(mgcosθ)*x*cosθ

Something tells me this is not correct... To be honest I'm completely lost on this one =( Thats as close as I could get, and its not one of the answer choices. I'd be really thankful for anyone who could help show me the process of deriving the work done by friction!

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# Homework Help: Finding Δx of a box sliding down an inclined plane using Work theory.

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