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## Homework Statement

A box of mass

*m*with an initial velocity of

*v*slides down a plane, inclined at

_{0}*θ*with respect to the horizontal. The coefficient of kinetic friction is

*μ*. The box stops after sliding a distance

*x*. How much work is done by friction?

## Homework Equations

Work=Force*

*x**cosθ

W=ΔKE

KE

_{0}=(.5)(m)(

*v*

_{0}^{2})

## The Attempt at a Solution

F

_{F}=(μ)(F

_{N})

F

_{Nety}=F

_{N}-F

_{gy}

0=F

_{N}-F

_{gy}

F

_{N}=F

_{gy}

F

_{gy}=mgcosθ

F

_{FK}=(μ)(F

_{N})

F

_{FK}=(μ)(mgcosθ)

Work=Force*

*x**cosθ

Work=(μ)(mgcosθ)*

*x**cosθ

Something tells me this is not correct... To be honest I'm completely lost on this one =( Thats as close as I could get, and its not one of the answer choices. I'd be really thankful for anyone who could help show me the process of deriving the work done by friction!

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