Finding dy/dt using the chain rule and a given equation

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Homework Help Overview

The discussion revolves around finding dy/dt using the chain rule in the context of an implicit differentiation problem involving the equation 4x^3 - 6xy^2 + 3y^2 = 228.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the application of the chain rule and implicit differentiation to find dy/dt. There are questions about how to incorporate previously calculated values into the equation to solve for dy/dt.

Discussion Status

Some participants have offered guidance on differentiating the given equation with respect to t and substituting known values. There is an exploration of the relationship between dy/dx and dy/dt, with one participant noting the need to include dx/dt in the expression for dy/dt.

Contextual Notes

Participants are working under the constraints of implicit differentiation and the need to relate derivatives through the chain rule. There is an emphasis on understanding the connections between the derivatives involved.

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Homework Statement



So I'm trying to find dy/dt. I used the chain rule to find dx/dt. I just don't understand how to put that answer back into an equation to find dy/dt

Homework Equations



4x^3-6xy^2+3y^2=228

The Attempt at a Solution


I found dx/dt=3 x=-3 and y=4
So how/what equation do I use to find dy/dt
 
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kweig said:

Homework Statement



So I'm trying to find dy/dt. I used the chain rule to find dx/dt. I just don't understand how to put that answer back into an equation to find dy/dt

Homework Equations



4x^3-6xy^2+3y^2=228

The Attempt at a Solution


I found dx/dt=3 x=-3 and y=4
So how/what equation do I use to find dy/dt

Differentiate 4x^3-6xy^2+3y^2=228 with respect to t, put your values for x, y and dx/dt into that and solve for dy/dt.
 
The implicit differentiation?
 
kweig said:
The implicit differentiation?

Of course.
 
I got dy/dt=(2x^2-y^2)/(y(2x-1))
 
kweig said:
I got dy/dt=(2x^2-y^2)/(y(2x-1))

An expression for dy/dt ought to have some dx/dt's in it. I think what you've got there is dy/dx. Can you think how to use that to get dy/dt?
 
Yep! I figured it out. Thank you!
 

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