Finding Effective Resistance Across A Hexagon: A Homework Solution

Click For Summary

Homework Help Overview

The discussion revolves around finding the effective resistance across points A and B in a circuit represented by a regular hexagon with resistances. Participants are exploring the implications of a resistance-less wire that passes through one of the diagonals of the hexagon.

Discussion Character

  • Exploratory, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • Participants are questioning the validity of removing the wire and its impact on the circuit's nodes. There is an attempt to simplify the circuit by identifying points of equal potential and combining resistors in series or parallel.

Discussion Status

Some participants have suggested redrawing the circuit to better visualize the connections and potential simplifications. Others express uncertainty about identifying points with the same potential and how to proceed with simplifying the circuit.

Contextual Notes

There is a mention of a resistance-less wire affecting the circuit's configuration, and participants are grappling with the implications of this on the overall analysis. The original poster has indicated difficulty in finding points with the same potential, which is central to the problem.

Asphyx820
Messages
9
Reaction score
0

Homework Statement



The diagram represents a regular hexagon. The resistances are r each
Find the effective resistance across points A & B

http://tinypic.com/r/153n39d/7


Homework Equations





The Attempt at a Solution



A resistance less wire passes through one of the diagonals. so can we remove the wire and then solve.
i tried but i didnt get the answer.
do none of the points have same potential
 
Physics news on Phys.org
What exactly do you mean by "remove the wire"? You can't just erase it because that would create more nodes than the original circuit has (all points connected by unbroken wire conductor belong to same node).
 
Asphyx820 said:
A resistance less wire passes through one of the diagonals. so can we remove the wire and then solve.
i tried but i didnt get the answer.
Show what you did.

I assume that when you "remove the wire" you mean that points connected by the wire can be joined. Do that and look for combinations of resistors in series or parallel that can be replaced by their equivalent. Step by step you can simplify this arrangement.
 
Try redrawing the circuit after you collapse the horizontal line into a point. [edit: what Doc said :redface:]
 
Ok ! so what do I do?
I can't find any points having same potential. how will i simplify the circuit?
 
Asphyx820 said:
Ok ! so what do I do?
I can't find any points having same potential. how will i simplify the circuit?
:confused: Points connected by a wire have the same potential.
 

Similar threads

  • · Replies 41 ·
2
Replies
41
Views
12K
Replies
3
Views
2K
  • · Replies 10 ·
Replies
10
Views
1K
  • · Replies 31 ·
2
Replies
31
Views
5K
Replies
8
Views
2K
  • · Replies 7 ·
Replies
7
Views
11K
  • · Replies 4 ·
Replies
4
Views
2K
  • · Replies 10 ·
Replies
10
Views
2K
  • · Replies 6 ·
Replies
6
Views
2K
  • · Replies 7 ·
Replies
7
Views
5K