Finding Eigenvectors for a Real Canonical Form of Matrix A

  • Thread starter Thread starter ItsKP
  • Start date Start date
  • Tags Tags
    Eigenvectors
ItsKP
Messages
2
Reaction score
0

Homework Statement


Let A= [0 2 1;-2 3 0;1 0 2]
Determine a real canonical form of A and give a change of basis matrix P that brings the matrix into this form.


Homework Equations





The Attempt at a Solution


I found my eigenvalues to be 0, 2+i and 2-i.
So, taking 2+i, I get the real canonical form
[0 0 0; 0 2 1; 0 -1 2].
Now using 2+i how do I find the eigenvalues to find a P that contains the 3 eigenvectors?
 
Physics news on Phys.org
i think your eigenvalues should be
1, 2+i and 2-i
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
Back
Top