Finding Electric Field from Electric Potential

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SUMMARY

The discussion focuses on deriving the electric field (E) from the electric potential (V) using partial derivatives to obtain the components Ex, Ey, and Ez. It emphasizes that the electric field is a vector quantity, requiring both magnitude and direction for proper representation. The components can be presented in raw form or as a magnitude with a specified direction, depending on the context of the problem.

PREREQUISITES
  • Understanding of electric potential (V) and electric field (E) concepts
  • Knowledge of vector mathematics and component analysis
  • Familiarity with partial derivatives in calculus
  • Basic principles of electromagnetism
NEXT STEPS
  • Study vector representation of electric fields and their components
  • Learn about the relationship between electric potential and electric field in electrostatics
  • Explore methods for visualizing vector fields in physics
  • Investigate applications of electric fields in various physical contexts
USEFUL FOR

Students in physics, electrical engineers, and anyone interested in understanding the relationship between electric potential and electric fields.

uchicago2012
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Hello,

I'm working on a problem where I'm given V, the electric potential, and asked to find E, the electric field. So I took the partial derivatives and found Ex, Ey, Ez. But now I was wondering how to present this answer, since it is the components of the electric field and not the electric field. Would I simply add them together? And how would I know the direction of E, since E is a vector while V is not?
 
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uchicago2012 said:
Hello,

I'm working on a problem where I'm given V, the electric potential, and asked to find E, the electric field. So I took the partial derivatives and found Ex, Ey, Ez. But now I was wondering how to present this answer, since it is the components of the electric field and not the electric field. Would I simply add them together? And how would I know the direction of E, since E is a vector while V is not?

The field is a vector quantity. It has magnitude and direction. You could present the result in raw component form, or as a magnitude with a direction specified either by angles, or perhaps as a unit vector in the appropriate direction. The precise form will depend upon the context, and how other vectors are specified in the given circumstances.
 

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