Finding electric flux through the circular cap of a sphere

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SUMMARY

The discussion centers on calculating the electric flux through a circular cap of a sphere surrounding a charged particle. The sphere has a radius of R = 1.40 m and contains a charge Q = 42.0 μC at its center. The initial calculation of electric flux using the incorrect area formula resulted in 2.62x105 Nm2/C, while the correct answer is 2.78x105 Nm2/C. Key insights include the necessity of using the correct surface area formula for the cap and understanding the concept of solid angles in relation to flux calculations.

PREREQUISITES
  • Understanding of electric flux and Gauss's Law
  • Familiarity with the formula for electric field E = (kq)/r2
  • Knowledge of the area of a spherical cap, A = π(h2 + a2)
  • Concept of solid angles and their relation to flux
NEXT STEPS
  • Study the derivation and application of Gauss's Law in electrostatics
  • Learn about the calculation of solid angles, specifically Ω = 2π(1 - cos(θ))
  • Explore the relationship between electric field strength and charge distribution
  • Investigate the implications of using different area formulas for spherical caps
USEFUL FOR

Students and educators in physics, particularly those focusing on electromagnetism, as well as anyone involved in solving problems related to electric flux and field calculations.

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Homework Statement


A sphere of radius R = 1.40 m surrounds a particle with charge Q = 42.0 μC located at its center as shown in the figure below. Find the electric flux through a circular cap of half-angle θ = 28.0°.
24-p-051.gif


Homework Equations


Φ = ∫E⋅dA
E
= (kq)/r2
A = πa2 where a = rsin(θ) --> from Archimedes's formula for area of a spherical cap [excluding the h term since it is along the surface]).

The Attempt at a Solution


First thing I did was calculate the electric field, using E = (kq)/r2 obtaining 1.928x105 N/C. Then using A = πa2 I found the area to be 1.357 m2. Finally using the flux equation I obtained Φ = 2.62x105 Nm2/C. This answer is incorrect and the correct answer is given as 2.78x105 Nm2/C. I am unsure my method is correct. Any suggestions?
 
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quaticle said:
[excluding the h term since it is along the surface]
Not sure what you mean, but h is not zero.
 
Doc Al said:
Not sure what you mean, but h is not zero.
I wasn't sure if the h (height) variable was needed since the portion I am supposed to calculate the flux through is a flat area on the surface of the sphere. I wasn't sure how to find the area of that, and through searches found Archimedes' formula shown in the op. I just re-calculated and when taking the height to be r*cos(θ) I am further from the correct answer. We haven't used the formula before, I had found it an assumed it suitable for these circumstances but do not think it is useful anymore...
 
quaticle said:
I wasn't sure if the h (height) variable was needed since the portion I am supposed to calculate the flux through is a flat area on the surface of the sphere.
Realize that you need the component of the field perpendicular to whatever area you choose. Using the spherical cap makes that easy.

quaticle said:
I just re-calculated and when taking the height to be r*cos(θ) I am further from the correct answer.
That's not the height.

Even better than all this: What fraction of the total flux goes through that cone of angle θ? (Think in terms of solid angles.)
 
quaticle said:

Homework Statement


A sphere of radius R = 1.40 m surrounds a particle with charge Q = 42.0 μC located at its center as shown in the figure below. Find the electric flux through a circular cap of half-angle θ = 28.0°.
24-p-051.gif
YVgNr.png


Homework Equations


Φ = ∫E⋅dA
E
= (kq)/r2
A = πa2 where a = rsin(θ) --> from Archimedes's formula for area of a spherical cap [excluding the h term since it is along the surface]).
?

You have used wrong formula for the surface area of the cap. It is A=pi(h2+a2) where a is the radius of the cap and h is its high. a= Rsin(θ) and h = R(1-cos(θ))
 
Doc Al said:
Even better than all this: What fraction of the total flux goes through that cone of angle θ? (Think in terms of solid angles.)
The fraction of flux we are interested in goes through θ°/360°, right? So find the total flux like one normally would then find that fraction of it?
 
quaticle said:
The fraction of flux we are interested in goes through θ°/360°, right? So find the total flux like one normally would then find that fraction of it?
Almost. But it's a sphere, not a circle. Hint: How many steradians make up a sphere?
 
Doc Al said:
Almost. But it's a sphere, not a circle. Hint: How many steradians make up a sphere?
I am not sure what a steradian is, but a quick google search tells me 4π steradians are in a sphere. Do I then multiple the fraction by 4π?
 
quaticle said:
I am not sure what a steradian is, but a quick google search tells me 4π steradians are in a sphere.
Good.

quaticle said:
Do I then multiple the fraction by 4π?
First you need to know how many steradians are in that cone of angle θ. Then find what fraction that is of the whole sphere.
 
  • #10
Doc Al said:
First you need to know how many steradians are in that cone of angle θ. Then find what fraction that is of the whole sphere.
And this can be done using Ω = 2π(1-cos(θ)) ? This will give me the solid angle of the cone and then I divide that by the total sr of a sphere (4π) to obtain the fraction of the whole through which the flux I need flows...
 
  • #11
quaticle said:
And this can be done using Ω = 2π(1-cos(θ)) ? This will give me the solid angle of the cone and then I divide that by the total sr of a sphere (4π) to obtain the fraction of the whole through which the flux I need flows...
Yes.
 
  • #12
Doc Al said:
Yes.
Awesome thanks a lot, using these ideas I was able to obtain the correct answer!
 
  • #13
Cool. :smile:
 

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