Finding element of inverse matrix

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SUMMARY

The discussion focuses on finding a specific element of the inverse matrix B of a given matrix A without using determinants or adjoints. The matrix A is defined as A = \begin{pmatrix} 1 & 2 & 3 & 4 \\ 9 & 8 & 2 & 0 \\ 17 & 2 & 0 & 0 \\ 1 & 0 & 0 & 0 \end{pmatrix}. The key insight is that the dot product of the first three rows of A with the fourth column of B equals 0, while the dot product of the fourth row of A with the fourth column of B equals 1. This leads to the equation 1b_1 + 0b_2 + 0b_3 + 0b_4 = 1, allowing for the determination of the element b_1.

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Yankel
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Hello all,

I have this matrix A

\[A=\begin{pmatrix} 1 &2 &3 &4 \\ 9 &8 &2 &0 \\ 17 &2 &0 &0 \\ 1 &0 &0 &0 \end{pmatrix}\]

B is defined as the inverse of A. I need to find the element in the first row and fourth column of B, without using determinants, so without using adjoint.

How should I do it then ?

Thanks !
 
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We know that the dot-product of the first 3 rows of $A$ with the fourth column of $B$ is 0, and the dot product of the fourth row of $A$ with the fourth column of $B$ is 1.

let's call this column vector $(b_1,b_2,b_3,b_4)$. We need to find $b_1$. From the last sentence of my previous paragraph, we know that:

$1b_1 + 0b_2 + 0b_3 + 0b_4 = 1$.

Your conclusion?
 
I didn't see this. Nice one, thanks !
 

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