Finding equation of a plane passing through a point with given direction vectors

Click For Summary
SUMMARY

The discussion focuses on finding the equation of a plane defined by two direction vectors, specifically <1,3,-1>/sqrt(11) and <-2,1,1>/sqrt(6), that passes through the point (1,2,3). The key method identified is the use of the cross product of the two direction vectors to obtain a normal vector for the plane. Once the normal vector is determined, the equation of the plane can be derived using the point-normal form of a plane equation.

PREREQUISITES
  • Understanding of vector operations, specifically cross products.
  • Familiarity with the point-normal form of a plane equation.
  • Basic knowledge of three-dimensional geometry.
  • Ability to manipulate and simplify vector expressions.
NEXT STEPS
  • Learn how to calculate the cross product of vectors in three-dimensional space.
  • Study the point-normal form of a plane equation in detail.
  • Explore examples of finding equations of planes using various direction vectors.
  • Practice problems involving vector operations and their applications in geometry.
USEFUL FOR

Students studying geometry, particularly those tackling problems involving planes and vectors, as well as educators looking for teaching resources on vector mathematics.

htoor9
Messages
16
Reaction score
0

Homework Statement


I need to find the equation of a plane with direction vectors <1,3,-1>/sqrt(11) and <-2,1,1>/sqrt(6) passing through the point (1,2,3)


Homework Equations





The Attempt at a Solution


I'm not really sure what to do, I was considering taking the cross product, but I'm not sure what that would leave. Thanks
 
Physics news on Phys.org
The cross product of two tangent vectors would give you a normal vector, wouldn't it? Can't you find the equation of the plane from a normal vector and a point on the plane?
 

Similar threads

Replies
1
Views
1K
Replies
7
Views
2K
Replies
4
Views
2K
  • · Replies 2 ·
Replies
2
Views
2K
Replies
6
Views
4K
  • · Replies 2 ·
Replies
2
Views
1K
  • · Replies 4 ·
Replies
4
Views
2K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 6 ·
Replies
6
Views
2K