Finding equivalent resistance in complicated circuit

  • Thread starter Tekee
  • Start date
  • #1
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Homework Statement



Problem: What single, equivalent resistor could replace all of the resistors in this circuit?
Given R1 = 4, R2 = 5, R3 = 14, R4 = 9

Homework Equations



In series, R1 + R2... = Req
Parallel, 1/R1 + 1/R2... = 1/Req

The Attempt at a Solution



I have tried multiple different possibilities of series/parallel. I thought for sure that R2/R4 are in parallel, that R1 was in series with 2/4 and that R3 was in parallel with 1/2/4. When I tried this answer, I got feedback that I was wrong.
 

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Answers and Replies

  • #2
648
2
I would say that R2 and R4 are in parallel, call it R5
R5 is in series with R3, call it R6
R6 is in parallel with R1
 
  • #3
2,051
317
Your first conclusion was correct, But R1 is not in series with R2/R4.

Two resistances are in series:
- if they are connected to each other with a wire.
- if nothing else connects to this wire.

The second condition fails because the battery is also connected to the connection between
R1 and R2/R4

try to look only at what is connected to what, and not where the resistances are drawn. direction.
 

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