Finding Force of Air Resistance on Parachutist Falling at 55km/h

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Homework Help Overview

The discussion revolves around calculating the force of air resistance acting on a parachutist who falls a certain distance after opening her parachute. The subject area includes concepts of dynamics and forces, particularly focusing on the effects of air resistance during free fall.

Discussion Character

  • Exploratory, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • Participants explore the relationship between speed, force, and acceleration, with some questioning the assumptions about constant speed and the calculations involved in determining net force and deceleration.

Discussion Status

Participants are actively engaging with the problem, attempting to clarify the relationship between forces and motion after the parachute opens. Some guidance has been offered regarding the need to calculate deceleration and net force, but there is no explicit consensus on the correct approach or final answer.

Contextual Notes

There is a mention of the need to convert speed into appropriate units and the importance of understanding the motion dynamics after the parachute opens. Participants are also navigating through potential misunderstandings regarding the calculations of forces involved.

SCA
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1. A parachutist of mass 62 kg is falling at 55 km/h when her parachute open. She then falls 24 m in the next 2.0 seconds. Find the force of air resistance acting on the parachute during those 2.0 seconds.2. Could I just find the force of friction?3. I found out what the force would be if not including air resistance 607.6N but I do not know how to find the force of air resistance
 
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If someone falls 24m in 2 secs, what is the most obvious thing you can calculate from that?
 
Speed is 12m per second
 
Is that a constant speed?
 
Yes
 
Are you sure about that?
 
Nope, I have no idea where to even start but I did try using:
Fnet=ma
which is Fnet=3410
and I subtracted the free fall acceleration of 607.6 and I ended up with 2802.4
Is that anything like what I need to do?
 
I don't know where you got that first number. Anyway, first you have to work out what happens when the parachute opens. Hint: Have you converted the initial speed into m/s?
 
I got it by doing mass times gravity, The initial speed is 15.29 m/s
 
  • #10
SCA said:
I got it by doing mass times gravity, The initial speed is 15.29 m/s
That's the right speed, although mass times gravity has nothing to do with it.

That means the parachutist slows down when the chute opens.

Can you see how to work out what the deceleration is?
 
  • #11
Yeah sorry I was answering your question about how I got the first number. Not really, is the deceleration the force of air resistance?
 
  • #12
SCA said:
Yeah sorry I was answering your question about how I got the first number. Not really, is the deceleration the force of air resistance?
You need to calculate the deceleration first.

Once you have that you calculate the nett force.

So you need to think carefully about the motion after the chute is opened and about what the 12 m/s represents.
 
  • #13
Thank you for all your help!
 
  • #14
So the Deceleration would be 12 m/s and then the net force would be 3.29 m/s?
 
  • #15
No never mind 3.29 would be the acceleration you use to calculate the net force?
 
  • #16
SCA said:
No never mind 3.29 would be the acceleration you use to calculate the net force?
You got the right answer but I'm not sure you know exactly why. You can go ahead and calculate the forces now. But you ought to justify that deceleration value.
 
  • #17
is the end answer 404.86?
 
  • #18
SCA said:
is the end answer 404.86?
No. That's less than the force due to gravity. Draw a diagram of the forces and you should see what is happening.
 

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