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x^2 + xy + y^2 = 25

my method was to implicitely differentiate and then set the numerator = 0 to get points of horizontal asymptotes, and then set the denominator = 0 to get the points for the veritcal asymptotes.

when i use implicit differentiation i get:

y' = (-2x - y)/(x + 2y)

am i correct so far? now im stuck because if i set the top equal to 0 i just get y = -2x. what can i do from here to solve for the points where there are both horizontal and vertical asymptotes? thanks.

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# Finding horizontal and vertical asymptotes

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