Finding Horizontal & Vertical Asymptotes Of A Curve

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SUMMARY

The discussion focuses on finding horizontal and vertical asymptotes of a curve. A vertical asymptote was initially identified at x = -3/8 using the quadratic formula, but further analysis revealed that there are no vertical asymptotes. The horizontal asymptotes were determined to be y = -1/2 and y = 1/2 by evaluating the limits of the function as x approaches ± ∞. This process involved rechecking calculations and understanding the implications of having a square root in the denominator.

PREREQUISITES
  • Understanding of limits in calculus
  • Familiarity with the quadratic formula
  • Knowledge of asymptotic behavior of functions
  • Basic algebraic manipulation skills
NEXT STEPS
  • Learn how to evaluate limits at infinity for rational functions
  • Study the properties of vertical and horizontal asymptotes
  • Explore the implications of square roots in rational expressions
  • Practice identifying asymptotes with various types of functions
USEFUL FOR

Students studying calculus, particularly those focusing on asymptotic analysis, and educators looking for examples of asymptote identification techniques.

CallMeShady
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Homework Statement


2ccpegg.jpg



Homework Equations


None


The Attempt at a Solution


I was able to find a vertical asymptote at x=-3/8 by setting the denominator to 0 and using the quadratic formula to find the roots. However, I am unsure of how to find the horizontal asymptotes, and I am not 100% confident that my vertical asymptote is correct. The confusion that I have here is with the square root in the denominator.
 
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CallMeShady said:

Homework Statement


2ccpegg.jpg


Homework Equations


None

The Attempt at a Solution


I was able to find a vertical asymptote at x=-3/8 by setting the denominator to 0 and using the quadratic formula to find the roots. However, I am unsure of how to find the horizontal asymptotes, and I am not 100% confident that my vertical asymptote is correct. The confusion that I have here is with the square root in the denominator.
Recheck that result you get from "setting the denominator to 0 and using the quadratic formula to find the roots".

For the horizontal asymptote(s), find the limit of your function as x → ± ∞ .
 
SammyS said:
Recheck that result you get from "setting the denominator to 0 and using the quadratic formula to find the roots".

For the horizontal asymptote(s), find the limit of your function as x → ± ∞ .

Thank you Sammy. After watching some videos regarding this topic and your assistance, I found out that the horizontal asymptotes are y=-1/2, 1/2 and there are no vertical asymptotes. Thank you again.
 

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