Finding induced emf of solenoid

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SUMMARY

The discussion focuses on calculating the induced electromotive force (emf) in a 15-turn coil wound around an 800-turn solenoid with a length of 18 cm and a diameter of 2.9 cm. The current in the solenoid increases from 0 to 3.1 A over 0.28 seconds. The correct formula for induced emf is Emf = -N * (delta_flux/delta_t), where delta_flux is derived from the magnetic field B calculated using B = (μ₀ * N * I) / l. The final induced emf calculated is 1.2 x 10^-5 V.

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  • Understanding of electromagnetic induction principles
  • Familiarity with solenoid magnetic fields
  • Knowledge of the formula for induced emf
  • Basic proficiency in using scientific calculators for physics calculations
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  • Study the derivation of the magnetic field inside a solenoid using Ampère's Law
  • Learn about Faraday's Law of electromagnetic induction in detail
  • Explore the concept of flux linkage in coils
  • Practice problems involving induced emf in various configurations of coils and solenoids
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number14
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Homework Statement


A 800-turn solenoid, 18 cm long, has a diameter of 2.9 cm. A 15-turn coil is wound tightly around the center of the solenoid.
If the current in the solenoid increases uniformly from 0 to 3.1 A in 0.28 s, what will be the induced emf in the short coil during this time?


Homework Equations



Emf=delta_flux/delta_t

The Attempt at a Solution


I keep getting the wrong answer. Originally I just plugged in 800 and 15 for the n's, but then I used turns per meter. Both were wrong. I think I may be using the wrong equation. Any help would be appreciated!
 
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Hi number14,

number14 said:

Homework Statement


A 800-turn solenoid, 18 cm long, has a diameter of 2.9 cm. A 15-turn coil is wound tightly around the center of the solenoid.
If the current in the solenoid increases uniformly from 0 to 3.1 A in 0.28 s, what will be the induced emf in the short coil during this time?


Homework Equations



Emf=delta_flux/delta_t

The Attempt at a Solution


I keep getting the wrong answer. Originally I just plugged in 800 and 15 for the n's, but then I used turns per meter. Both were wrong. I think I may be using the wrong equation. Any help would be appreciated!

What did you do to get your answers? (what equations did you use, and what numbers did you plug into them)
 
I used B=(mu_0 *N*I)/l delta_flux = B*pi*r^2 and
Emf=-N * delta_flux/delta_t

N=15, I=3.1, l=.18, delta_t=.28 , r=.0145

and I got: 3.6 * 10^-5
 
number14 said:
I used B=(mu_0 *N*I)/l delta_flux = B*pi*r^2 and
Emf=-N * delta_flux/delta_t

N=15, I=3.1, l=.18, delta_t=.28 , r=.0145

and I got: 3.6 * 10^-5

I'm not getting that answer from using those numbers. What are you getting for just the B part by itself?
 
Last edited:
B=3.3*10^-4
 
Wait, this time i got 1.2*10^-5 . I'm using a calculator that is very finicky.
 
number14 said:
B=3.3*10^-4

I think here you are using N=15; but the B is the magnetic field from the solenoid, which has N=800.
 
thanks so much for the help, i got the right answer finally!
 

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