Finding induced emf of solenoid

1. Mar 5, 2009

number14

1. The problem statement, all variables and given/known data
A 800-turn solenoid, 18 cm long, has a diameter of 2.9 cm. A 15-turn coil is wound tightly around the center of the solenoid.
If the current in the solenoid increases uniformly from 0 to 3.1 A in 0.28 s, what will be the induced emf in the short coil during this time?

2. Relevant equations

Emf=delta_flux/delta_t

3. The attempt at a solution
I keep getting the wrong answer. Originally I just plugged in 800 and 15 for the n's, but then I used turns per meter. Both were wrong. I think I may be using the wrong equation. Any help would be appreciated!

2. Mar 5, 2009

alphysicist

Hi number14,

What did you do to get your answers? (what equations did you use, and what numbers did you plug into them)

3. Mar 6, 2009

number14

I used B=(mu_0 *N*I)/l delta_flux = B*pi*r^2 and
Emf=-N * delta_flux/delta_t

N=15, I=3.1, l=.18, delta_t=.28 , r=.0145

and I got: 3.6 * 10^-5

4. Mar 6, 2009

alphysicist

I'm not getting that answer from using those numbers. What are you getting for just the B part by itself?

Last edited: Mar 6, 2009
5. Mar 6, 2009

B=3.3*10^-4

6. Mar 6, 2009

number14

Wait, this time i got 1.2*10^-5 . I'm using a calculator that is very finicky.

7. Mar 6, 2009

alphysicist

I think here you are using N=15; but the B is the magnetic field from the solenoid, which has N=800.

8. Mar 6, 2009

number14

thanks so much for the help, i got the right answer finally!!!