Finding Ix in Switch Circuit at Different Times

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    Circuit Switch
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Discussion Overview

The discussion revolves around analyzing the current Ix in a switch circuit at different time intervals (0-, 0+, and 40ms) after the switch is opened at t=0. The focus is on the behavior of the current through an inductor and the assumptions made in the calculations.

Discussion Character

  • Homework-related
  • Technical explanation
  • Debate/contested

Main Points Raised

  • One participant calculates Ix as 0.3A for both 0- and 0+ by using the formula Ix=3v/10Ω.
  • Another participant questions whether the current through an inductor can change instantaneously, suggesting that this is a critical aspect to consider.
  • A participant presents their calculation for τ (tau) as 7.14ms using τ=L/R, indicating uncertainty about the current at 40ms.
  • There is a request for clarification on the assumptions made regarding the current when the switch is open and closed.
  • Concerns are raised about the ambiguity of the circuit diagram and the timing of the switch's state changes.

Areas of Agreement / Disagreement

Participants do not reach a consensus on whether the current through the inductor can change instantaneously, and there is uncertainty regarding the calculations for the current at 40ms. The discussion remains unresolved with multiple viewpoints presented.

Contextual Notes

There are limitations regarding the assumptions made about the circuit's behavior before and after the switch operation, as well as the clarity of the circuit diagram, which may affect the interpretations of the problem.

jeuceda
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Homework Statement


Assume that the switch in the figure has been closed for a long time and opens after in t=0.
Find Ix in a) 0- b)0+ c) 40ms
upload_2015-9-21_19-36-19.png

The Attempt at a Solution


Switch is opened in t=0, current flows only in the 10Ω resistor, Ix=3v/10Ω= 0.3A-> 0-
0+ --> 3v/10=0.3A
Not sure if both currents are the same, and for the 40ms, when solving the equation (τ=L/R) τ (tau) results in a small number.
 
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Do you think it's possible for the current through an inductor to change instantaneously?

It might help to see your work for part c in order to check it.
 
axmls said:
Do you think it's possible for the current through an inductor to change instantaneously?

It might help to see your work for part c in order to check it.

No couldt change instantaneously.
this is what i have for part c
τ=L/R -> (500mH)/70Ω=7.14ms

i(t)= i(∞)-(i(∞)-i(0+))e^(-t/τ)
i(40)= ?

That where I am stuck
 
Hi jeuceda. :welcome:

jeuceda said:

The Attempt at a Solution


when the switch is open Ix=3v/10Ω= 0.3A
What assumptions allow you to say this?

When the switch is closed Ix=0.3A
How did you calculate this?

Not sure if both currents are the same, and for the 40ms, when solving the equation τ (tau) results in a small number.
You mention an equation. What is your equation, exactly?

It is clearer when you include a phrase such as "at the moment before the switch is closed ...", or "once the switch has been open for a long time ...", to confirm precisely what you are talking about.

BTW, the diagram is ambiguous; it is not clear from the diagram whether at time t=0 the switch is opened after having already been closed for a long time, or whether it is being closed at t=0 having prior to this been open for a long time. The textbook's double-headed arrow would be better drawn with only one arrow head.
 

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