Finding loss of sun's mass given the energy density delivered.

AI Thread Summary
To calculate the sun's mass loss over one year based on the energy density of 1300 J/m²s at Earth's surface, one must first convert energy density into total energy received by Earth. The total energy can be found by multiplying the energy density by the surface area of a sphere with a radius equal to the distance from the Earth to the sun. Using the equation ΔE = Δmc², the mass loss can then be derived from the total energy over the year. It's important to recognize that energy density is not the same as total energy, which requires careful consideration in calculations. The discussion highlights the need for clarity in distinguishing between energy density and total energy when applying relevant equations.
texan14
Messages
7
Reaction score
0

Homework Statement



The energy density (energy per unit area per unit time) arriving from the sun at the surface of the Earth is 1300 J/m2s. Calculate the mass loss of the sun in one year. (The Earth is about 1.49 x 1011 m from the sun.)

Homework Equations



ΔE = Δmc2

KE = (γ-1)mc2

The Attempt at a Solution



I'm not sure how to calculate the loss of energy density from the sun as a function of distance. I feel like it can't be as easy as plugging the energy into E=mc2
 
Physics news on Phys.org
Hint: You're not given an energy; you're given an energy density.
 
Thread 'Collision of a bullet on a rod-string system: query'
In this question, I have a question. I am NOT trying to solve it, but it is just a conceptual question. Consider the point on the rod, which connects the string and the rod. My question: just before and after the collision, is ANGULAR momentum CONSERVED about this point? Lets call the point which connects the string and rod as P. Why am I asking this? : it is clear from the scenario that the point of concern, which connects the string and the rod, moves in a circular path due to the string...
Back
Top