In wandering, a grizzly bear makes a displacement of 1563m due west, followed by a displacement of 3348m in a direction 32 degrees NW. What are the (a) the magnitude and (b) the direction of the displacement needed for the bear to return to its starting point? Specify the direction relative to due east.
R2 = A2 + B2 – 2ABcosθ
The Attempt at a Solution
a. magnitude= (1563^2)+ (3348^2)-2(1563)(3348)cos32=2185.53 m
I don't know if i am right though cuz i don't understand what they mean by "due east"