Finding mass within a pulley system. Finding coefficient of friction

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Homework Help Overview

The discussion revolves around a physics problem involving a pulley system, specifically focusing on finding the mass of an object within the system and determining the coefficient of friction for a toboggan on snow. The context includes a block accelerating on a frictionless table and a toboggan decelerating on snow.

Discussion Character

  • Mixed

Approaches and Questions Raised

  • Participants discuss the relationship between tension, mass, and acceleration, with some attempting to derive the mass using force equations. Questions arise about the combined mass of the system and the forces acting on it.

Discussion Status

There are multiple lines of reasoning being explored, with some participants suggesting the need to consider the combined mass for acceleration calculations. Guidance has been offered regarding the interpretation of forces involved in the system.

Contextual Notes

Participants express uncertainty about the minimal information provided for finding the mass and the coefficient of friction, indicating a need for clarity on the assumptions being made in the problem setup.

Serendipitydo
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Ok so I'm in college upgrading, and doing my physics 20. I have a hand in assignment due Wednesday and I can't for the life of me figure out these two questions.

6. The 4.0kg block shown accelerates across a frictionless horizontal table at 1.5m/s2.
Find the mass of object m1
PhysicsQ6.png

A. 0.61kg B. 0.72kg C. 6.0kg D. 26kg

For m1 I have: FN=Fg. Fg=mg, so 39N. FT-0(no Ff)=ma . So FT is 6.0N. And then I'm lost. 8. A 45kg toboggan and rider decelerate on level show at 0.53m/s2. What is the coefficient of friction between the toboggan and the snow?

A. 0.012 B. 0.054 C. 0.22 D. 0.53

I got that FN=Fg. Fg=mg so 441.45N(rounded to 2SD). Fnet=ma so 24N. And then I'm lost. I know that μ=Ff/FN

Someone help me please!
 
Last edited:
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You have a combined mass of M1 + M2 being accelerated (together). Write an equation for the force that is needed to accelerate such a mass.
 
I got the mass...I think. FT=ma. 6.0N=m1(9.81m/s2) So m1=0.6112kg

Now for the other one...
 
Serendipitydo said:
I got the mass...I think. FT=ma. 6.0N=m1(9.81m/s2) So m1=0.6112kg

Now for the other one...


---
Ok I think I solved it. Ff is Fnet in the direction of acceleration? So since it's decelerating, wouldn't it accelerate in the direction of the friction?

So Ff=ma
Ff=24N

μ=Ff/FN
μ=24N/441N
μ=0.05442
 
Serendipitydo said:
I got the mass...I think. FT=ma. 6.0N=m1(9.81m/s2) So m1=0.6112kg

Now for the other one...
Not so fast. You haven't got this one right, yet. You must determine the force needed to accelerate the combined masses, since they accelerate together.
 
NascentOxygen said:
Not so fast. You haven't got this one right, yet. You must determine the force needed to accelerate the combined masses, since they accelerate together.

But I only need the mass of the one.
 
NascentOxygen said:
You have a combined mass of M1 + M2 being accelerated (together). Write an equation for the force that is needed to accelerate such a mass.

NascentOxygen has asked you this question for a reason. Answering it will help you answer the question asked in the problem. More importantly, it should help you understand how to approach such a problem in general.
 
SammyS said:
NascentOxygen has asked you this question for a reason. Answering it will help you answer the question asked in the problem. More importantly, it should help you understand how to approach such a problem in general.
I'm not having problems with the others, just when I need to find a mass with minimal info.
Fg1-FT=ma
Use the total mass of the system. The difference of force of gravity and tension on the rope would be the net force acting on the system.
 
Last edited:
The question supplies all the information you need. You have a mass (M1 + M2) being accelerated. The force that is causing the acceleration is the weight of M1.

One equation, one unknown.
 
  • #10
Serendipitydo said:
---
Ok I think I solved it. Ff is Fnet in the direction of acceleration? So since it's decelerating, wouldn't it accelerate in the direction of the friction?

So Ff=ma
Ff=24N

u=Ff/FN
u=24N/441N
u=0.05442

That looks right.
 
  • #11
Thanks for your help. I tend to overthink these things
 

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