Finding Pelican's Initial Speed and Distance Traveled by Fish - Can You Help Me?

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A pelican drops a fish from a height of 4.9 m, and the fish travels 7.5 m horizontally before hitting the water. To find the pelican's initial speed, the relevant equations of motion are discussed, particularly focusing on the horizontal and vertical components of the drop. The equation s = 1/2gt² is clarified, emphasizing that 's' represents distance, not speed. After some confusion, the correct approach using Vx = deltaX/t is confirmed to yield the right answer. The discussion highlights the importance of understanding the definitions of variables in physics equations.
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A pelican flying along a horizontal path drops
a fish from a height of 4.9 m. The fish travels
7.5 m horizontally before it hits the water
below.
What was the pelican’s initial speed? The
acceleration of gravity is 9.81 m/s^2
Answer in units of m/sIf the pelican was traveling at the same speed
but was only 3.0 m above the water, how
far would the fish travel horizontally before
hitting the water below?
Answer in units of mCan someone help me i have no idea how to solve this I am lost.
 
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Sure. You did well on nuber one of the template. Now help us to provide adequate assistance (at the right level) by also completing 2 and 3. PF rules don't allow us to help if you don't . Why ? See the guidelines !

1. Homework Statement

Homework Equations


3. The Attempt at a Solution
[/B]
And eh, welcome to PF !
 
BvU said:
Sure. You did well on nuber one of the template. Now help us to provide adequate assistance (at the right level) by also completing 2 and 3. PF rules don't allow us to help if you don't . Why ? See the guidelines !

1. Homework Statement

Homework Equations


3. The Attempt at a Solution
[/B]
And eh, welcome to PF !

ok number 2 is

vx
dx 7.5
t

vfY
voY 0
aY -9.8
dY -4.9
t

i used this equation

s=1/2gt^2

but i can get the right answers

and number 3 is

i used that equation but i can´t get the right answerand sorry I am new idk how to ask correctly here and stuff
 
s=1/2gt^2
When you use this equation, what is the result telling you?
 
2. ) s=1/2gt^2
What is s ?
 
BvU said:
What is s ?
s is speed
 
BvU said:
What is s ?

like i get the wrong answer all the time
 
Like you multiply m/s^2 with s^2 and you are surprised you don't get something with the dimension of m/s ?
 
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Mitxigan said:
s is speed
No, in the standard SUVAT equations s is distance. Speeds, initial and final, are represented by u and v.
 
  • #10
BvU said:
Like you multiply m/s^2 with s^2 and you are surprised you don't get something with the dimension of m/s ?
No is just that i get the answer wrong not the dimensions
 
  • #11
So now apply the equation I quoted, and describe what it can tell you. (Remember, s is not speed.)
 
  • #12
NascentOxygen said:
So now apply the equation I quoted, and describe what it can tell you. (Remember, s is not speed.)
haruspex said:
No, in the standard SUVAT equations s is distance. Speeds, initial and final, are represented by u and v.

I used the equation Vx=deltaX/t

And i got it right thanks tho ;)
 
  • #13
Mitxigan said:
I used the equation Vx=deltaX/t

And i got it right thanks tho ;)
That's the only equation you used? Since you showed no working here, we'll have to accept your word that you solved it correctly.
 
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