Finding power series for given values of a sum

Telemachus
Messages
820
Reaction score
30

Homework Statement


I have this exercise which I'm not sure how to solve.
It says: Consider the series \displaystyle\sum_{0}^{\infty}x^n Does exists any value of x for which the series converges to five? ¿and to 1/3?

Well, I've reasoned that if there exists that value, then it must be inside of the radius of convergence for the series. So I've found the radius of convergence:

a_n=1

R=\displaystyle\lim_{n \to{}\infty}{\left |{\displaystyle\frac{a_n}{a_{n+1}}}\right |}=1

But now I don't know how to proceed.
 
Last edited:
Physics news on Phys.org
First of all, your formula for the radius of convergence looks a bit off. Where is the 1/2 coming from? And where is the x? That said, finding the radius of convergence will only let you know what values of x will allow the series to converge, not what it will converge to.

Do you know what the geometric series is? When does it converge? What does it converge to?
 
Sorry, I've corrected it, I did a_{n+1}=2 but its 1, I've just corrected it.

Thanks.
 
\sum_{n= 0}^\infty x^n[/itex] is a <b>geometric series</b>. There is a simple formula for its sum. Do you know what it is?
 
Yes, thanks. I've found it. I didn't realized it was a geometric series because I haven't been dealing with series for a while, but it was easy :)
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
Back
Top