Finding Q(point charge) with an angle, mass, and radii only

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To determine the static charge on two balls using Coulomb's law and equilibrium concepts, the relevant parameters include a distance of 3.3 cm, mass of 0.085 g for each ball, and an angle of 9.4 degrees. The discussion emphasizes the importance of analyzing the x and y components of forces, including gravity, tension, and the electric field. A free-body diagram is recommended to visualize the forces acting on one ball, followed by applying Newton's second law in both directions. The lab's context involves hanging the balls from a pivot and measuring the angle formed. This approach will help in solving for the charge using the provided data.
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Homework Statement


To find the amount of static charge on the balls using coulomb's law and the concepts of equilibrium.

r = 3.3 cm
m1 = .085g
m2 = .085g
\vartheta = 9.4\circ

Homework Equations



F = K(q1)(q2)\r2

The Attempt at a Solution


I legitimately have no clue how to do this other than the fact that r = 9.4...
Any tips/help will be appreciated.
 
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If you could post the actual question it would be helpful. You simply can't solve that with the information you provided.
 
Sorry...but it's a lab so we don't have an actual question and we apparently have all the data we need. to solve for q.

We have a hint that states, "Remember the key to solving the lab lies in figuring out the x and y vectors."

I'm assuming parts of the vector is composed of gravity, tension, and the electric field which separated the balls from each other.
 
Let me guess: this lab involves hanging two balls side by side from a common pivot point, and measuring the angle that the strings make at the pivot. Yes? If so, start by drawing a free-body diagram for one ball, then writing out Newton's second law for both x and y directions.
 
Yeah, that is exactly the lab we did. Thank you very much! I love this forum now.
 
Thread 'Variable mass system : water sprayed into a moving container'

Thread 'Variable mass system : water sprayed into a moving container'

Starting with the mass considerations #m(t)# is mass of water #M_{c}# mass of container and #M(t)# mass of total system $$M(t) = M_{C} + m(t)$$ $$\Rightarrow \frac{dM(t)}{dt} = \frac{dm(t)}{dt}$$ $$P_i = Mv + u \, dm$$ $$P_f = (M + dm)(v + dv)$$ $$\Delta P = M \, dv + (v - u) \, dm$$ $$F = \frac{dP}{dt} = M \frac{dv}{dt} + (v - u) \frac{dm}{dt}$$ $$F = u \frac{dm}{dt} = \rho A u^2$$ from conservation of momentum , the cannon recoils with the same force which it applies. $$\quad \frac{dm}{dt}...
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