Finding Range of the Projectile

  • Thread starter Abhi13
  • Start date
  • #1
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Hi All,

I have a question regarding finding the range of the projectile given the projectile crosses points P1(a,b) and P2(b,a).

I know any point on the projectile curve satisfies following equation:
y = x.tan \{theta} (1- (range/x))

therefore, the only thing remains to be found out is tan \{theta}.

Can anyone please direct me in finding \theta given these two point- P1(a,b) and P2(b,a).

Thanks,
Abhi
 

Answers and Replies

  • #2
2,544
2
By range do you mean from the lowest y value to the highest y value ,
or the difference between the x values .
Like when i throw a golf ball the range it traveled over the ground . In that sense
 
  • #3
2
0
By range do you mean from the lowest y value to the highest y value ,
or the difference between the x values .
Like when i throw a golf ball the range it traveled over the ground . In that sense
By range i mean the distance it travelled in the horizontal direction. Thats the difference between the values of x from where it took off to where it will land..
 
  • #4
2,544
2
I'm confused by your equation you have .
is it y=x*tan(q)(1-r/x)
 

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