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Finding Range of the Projectile

  1. Aug 7, 2010 #1
    Hi All,

    I have a question regarding finding the range of the projectile given the projectile crosses points P1(a,b) and P2(b,a).

    I know any point on the projectile curve satisfies following equation:
    y = x.tan \{theta} (1- (range/x))

    therefore, the only thing remains to be found out is tan \{theta}.

    Can anyone please direct me in finding \theta given these two point- P1(a,b) and P2(b,a).

    Thanks,
    Abhi
     
  2. jcsd
  3. Aug 13, 2010 #2
    By range do you mean from the lowest y value to the highest y value ,
    or the difference between the x values .
    Like when i throw a golf ball the range it traveled over the ground . In that sense
     
  4. Aug 14, 2010 #3
    By range i mean the distance it travelled in the horizontal direction. Thats the difference between the values of x from where it took off to where it will land..
     
  5. Aug 14, 2010 #4
    I'm confused by your equation you have .
    is it y=x*tan(q)(1-r/x)
     
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