Finding resistane and current non-ohmic

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To find the resistance R in the circuit with a 10.0-μF capacitor charged by a 10.0-V battery, the time constant τ (RC) can be utilized since the circuit is non-ohmic. Given that the capacitor reaches a potential difference of 4.00 V after 3.00 seconds, the equation i = - (CV_ab / RC)e^(-t/RC) can be applied to determine the current at that time. The relationship between voltage, capacitance, and time allows for the calculation of R using the known values. The time constant is crucial for solving this problem as it relates the resistance and capacitance in the charging process. Understanding the time constant helps to clarify the behavior of the circuit during charging.
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Homework Statement


A 10.0-μF capacitor is charged by a 10.0-V battery through a resistance R. The capacitor reaches a potential difference of 4.00 V at the instant 3.00 seconds after charging begins
1.) Find R
2.) Find the current at t=3.00 seconds after charging begins.


Homework Equations


i=\frac{dq}{dt}=-\frac{CV_{ab}}{RC}e^{-t/RC}


The Attempt at a Solution


so obviously I know how to find current but I need to find resistance and I cannot use R=V/I because it is non-ohmic! what do I do?
 
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Find the time constant ##\tau = RC##. You know C...
 
why am i using time constant?
 
Eagle's Wings said:
why am i using time constant?

Read the question carefully. Some information you're given involves time. If you can find the time constant RC and you already know C then...
 
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