Finding Solutions for z in z^2 = a + bi

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SUMMARY

The discussion focuses on solving the equation z^2 = a + bi, where a and b are real numbers. The solution involves letting z = x + iy and expanding the equation to compare real and imaginary parts, resulting in a system of equations. A key point is recognizing that the equation can be transformed into a quadratic form in terms of y^2, specifically 0 = y^4 + ay^2 - b^2/4. This allows for substitution to simplify the problem and find solutions for y.

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Bubblegum
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Homework Statement



z^2 = a + bi

a = real number
b = real number

find all the solutions for z

Homework Equations





The Attempt at a Solution



(x+y)^2 = a + bi ?
 
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Bubblegum said:

Homework Statement



z^2 = a + bi

a = real number
b = real number

find all the solutions for z

Homework Equations


The Attempt at a Solution



(x+y)^2 = a + bi ?

Let z = x+iy

Then

(x+iy)^2 = a+ib.

Expand the LHS and then compare the real parts and imaginary parts. Then what you'll have is a system of two equations in the two unknown x and y.
 
I am stuck at:

0= y^4 + ay^2 - b^2/4
 
Bubblegum said:
I am stuck at:

0= y^4 + ay^2 - b^2/4

It's a quadratic in y^2. If you're unsure what that means, let some other variable such as m=y2 and then solve for m, and then convert back to y2 and solve for y.
 

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