Finding Sphere Diameter for Radiation Equilibrium?

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Homework Help Overview

The problem involves determining the diameter of a sphere of water needed to achieve radiation equilibrium at its center, specifically for a uniform dilute solution of 60Cobalt gamma rays. The context is rooted in radiological physics, focusing on the attenuation coefficients for gamma radiation.

Discussion Character

  • Exploratory, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • Participants discuss the use of exponential attenuation equations to find the necessary diameter, questioning the role of the attenuation coefficients u and u(en). There is also a search for reliable values for these coefficients, with one participant expressing difficulty in obtaining them.

Discussion Status

Some participants have attempted to solve the problem using different approaches, including exponential attenuation and the build-up factor from the textbook. However, there are discrepancies in the results, leading to further inquiries about potential errors in their calculations or assumptions. Guidance has been offered regarding where to find the necessary attenuation coefficients.

Contextual Notes

There is a mention of specific values for the attenuation coefficients being sought, and participants are working under the constraints of textbook references and the need for accurate data to proceed with their calculations.

kmoh111
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Homework Statement


This problem comes from Frank Attix's book Intro to Radiological Physics and Rad Dosimetry.
From ch. 4 - problem #1:

Approximately what diameter for a sphere of water would be required to approach radiation equilibrium wihin 1% at its center, assuming it contains a uniform dilute solution of 60Cobalt (1.25 MeV gamma rays). Use u(en) and u as approximations to the effective gamma ray attenuation coefficient; this will over- and under-estimate the size respectively.



Homework Equations



u - is the attenuation coefficient for primary photons only
u(en) - is the effective attenuation coefficient for ideal broad beam attenuation


Attix gives the solutions as 312 cm and 144 cm


The Attempt at a Solution



I come close to one of the answers but I'm not sure how u and u(en) come into play here.

(4/3) pi r^3 = .01(1.25MeV).

This gives r = .144
 
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This thread can be disregarded. I was able to solve the problem.

The solution to this problem is to use exponential attenuation:

N = N(0) exp(-uL). The approach is to solve for L for given u and u(en) values when 99% of the photons are allowed to pass thru the sphere.
 
kmoh111 said:
This thread can be disregarded. I was able to solve the problem.

The solution to this problem is to use exponential attenuation:

N = N(0) exp(-uL). The approach is to solve for L for given u and u(en) values when 99% of the photons are allowed to pass thru the sphere.





hi..one of my classmates has asked about this problem too, i was thinking of this solution too, but i can't find the real values for u(en) and u...

i would like to ask, where can i find those values, i keep searching the net but gave me none... hope you would help us.

thanks :)

andy from philippines

God bless
 
thank you so much kmoh111

God bless :)
 
hi me again :(

ive tried to solve the problem using exponential attenuation but i always got a different answer...however i tried to use equation 3.14 (build up factor) in attix book... where B is approximately equal to 1.06... here's how it went..

0.99 = (1.06) exp(-uL) and 0.99 = (1.06) exp(u(en)L)

i used u = 0.46903 and u(en)= 0.216626 (this is base from the link that you've given me before)

but i got, L = 0.145 cm and L = 0.313 cm :( Attix gives the solutions as 312 cm and 144 cm



did i lack something in my equation? :(

pls help us...any comments will be very much appreciated

million thanks..


andy :(
 
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