- #1

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I don't quite understand how I would I find or construct subgroups for a permutation group?

Any advice?

Thanks

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- Thread starter RVP91
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- #1

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I don't quite understand how I would I find or construct subgroups for a permutation group?

Any advice?

Thanks

- #2

lavinia

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I don't quite understand how I would I find or construct subgroups for a permutation group?

Any advice?

Thanks

1 ->2 ->3 ->4 ->1

1 ->3 ->2 ->4 ->1 for example

- #3

jgens

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I used (1 2 3 4) and generated a subgroup of order 4, this subgroup was, {id, (1234), (13)(24), (1432)}, is this correct? And this is of order 4 so meets the condition.

I also did the same with (1324).

After reading a theorem I concluded if I want the subgroups to be of order 4 then the elements of the subgroups must divide 4. So since I've done the two for 4 would I know need to do the same for elements of order 2? Is there a shortcut or do I have to compute them all to check they form subgroups of order 4?

After attempting this with for example (12)(34) I found the usual method of multiplying by itself to try and find a group quickly failed since (12)(34)(12)(34) is simply id.

How do I find the subgroups using elements of order 2?

Thanks for the previous advice and an advance thanks for anymore

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