Finding the acceleration of a balloon

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SUMMARY

The discussion focuses on calculating the acceleration of a weather balloon with a mass of 5 kg and a radius of 2.879 m, carrying an additional load of 10 kg. The balloon is filled with helium, which has a density of 1.16 kg/m³, while the surrounding air has the same density. Participants emphasize the importance of buoyant force and weight in determining acceleration immediately after release, rather than relying solely on Bernoulli's equation or escape speed calculations.

PREREQUISITES
  • Understanding of buoyant force and its calculation
  • Familiarity with Bernoulli's equation
  • Knowledge of basic physics concepts such as mass and density
  • Ability to apply Newton's second law of motion
NEXT STEPS
  • Calculate buoyant force using the formula: Buoyant Force = Volume of Balloon × Density of Air × g
  • Determine the net force acting on the balloon and load system
  • Apply Newton's second law to find acceleration: a = Net Force / Total Mass
  • Explore the relationship between buoyancy and acceleration in fluid dynamics
USEFUL FOR

Physics students, engineers, and anyone interested in fluid dynamics and the mechanics of buoyancy in atmospheric conditions.

kelsif
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1. An empty spherical weather balloon with a mass of 5 kg has a radius of 2.879 m when fully inflated with helium. It is supposed to carry a small load of instruments having a mass of 10 kg. Taking air and helium to have densities of 1.16 kg/m^3, respectively, what will be the acceleration of the balloon and load immediately after it is released?



2. i have a= v^2/r and Bernoulli's equation P1+.5(pv1^2+pgy1)=P2+.5(pv2^2+pgy2)



3. I keep trying to figure a way to manipulate Bernoulli's equation to solve for v to plug into the first equation but can't get it to work. I also tried solving for escape speed (vesc=the square root of 2GM/R). But that doesn't use the densities. I'm extremely confused at this point.
 
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Do you need Bernoulli's equation?
Isn't it simply buoyant force upward and weight down.

Remember immediately after release it has no velocity
 
no i have bernoulli's equation but i don't know how to solve for the acceleration immediately after release...
 

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