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Finding the area between curves

  • Thread starter FARADAY JR
  • Start date
  • #1
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0

Homework Statement



find the area bounded by :
4x+y^2=12
x=y

Homework Equations




The Attempt at a Solution


f(x)= √4x-12
g(X)= x
√4x-12=x
√3x-12=0


I'm lost how am i supposed to set them equal to each other if the second equation is y=x? can anybody help me please
 
Last edited:

Answers and Replies

  • #2
tiny-tim
Science Advisor
Homework Helper
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Hi FARADAY JR! :smile:

(pleeease don't give different threads the same name! :redface:)
find the area bounded by :
4x+y^2=12
x=y

I'm lost how am i supposed to set them equal to each other if the second equation is y=x?
(where did √3x-12=0 come from? :confused:)

just replace y2 by x2 :wink:
 
  • #3
21
0
Hi FARADAY JR! :smile:

(pleeease don't give different threads the same name! :redface:)


(where did √3x-12=0 come from? :confused:)

just replace y2 by x2 :wink:
Ok, So
4x+x^2-12=x
3x+x^2-12=0
3 (x+2)(x-2)=0 ?
 
  • #4
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what do i do next?
 
  • #5
tiny-tim
Science Advisor
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4x+x^2-12=x
nooo :redface: … where did that x on the RHS come from? :confused:
 
  • #6
21
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nooo :redface: … where did that x on the RHS come from? :confused:
I was trying to do f(x)-g(x)=0
so I can find the high and low
 
  • #7
21
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so should I do it like this:
4x+x^2-12=0
(x+6)(x-2)=0
where X = 2,-6
?
 
  • #8
tiny-tim
Science Advisor
Homework Helper
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Yup! :biggrin:

(and now can you get the area? :wink:)
 

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