Finding the area between curves

Homework Statement

find the area bounded by :
4x+y^2=12
x=y

The Attempt at a Solution

f(x)= √4x-12
g(X)= x
√4x-12=x
√3x-12=0

I'm lost how am i supposed to set them equal to each other if the second equation is y=x? can anybody help me please

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tiny-tim
Homework Helper

(pleeease don't give different threads the same name! )
find the area bounded by :
4x+y^2=12
x=y

I'm lost how am i supposed to set them equal to each other if the second equation is y=x?
(where did √3x-12=0 come from? )

just replace y2 by x2

(pleeease don't give different threads the same name! )

(where did √3x-12=0 come from? )

just replace y2 by x2
Ok, So
4x+x^2-12=x
3x+x^2-12=0
3 (x+2)(x-2)=0 ?

what do i do next?

tiny-tim
Homework Helper
4x+x^2-12=x
nooo … where did that x on the RHS come from?

nooo … where did that x on the RHS come from?
I was trying to do f(x)-g(x)=0
so I can find the high and low

so should I do it like this:
4x+x^2-12=0
(x+6)(x-2)=0
where X = 2,-6
?

tiny-tim