Finding the area between curves

In summary, the conversation is about finding the area bounded by the equations 4x+y^2=12 and x=y. The attempt at a solution involved setting the equations equal to each other by replacing y^2 with x^2, resulting in (x+6)(x-2)=0. The solutions for x were found to be 2 and -6, but the area calculation was not yet completed.
  • #1
FARADAY JR
21
0

Homework Statement



find the area bounded by :
4x+y^2=12
x=y

Homework Equations

The Attempt at a Solution


f(x)= √4x-12
g(X)= x
√4x-12=x
√3x-12=0I'm lost how am i supposed to set them equal to each other if the second equation is y=x? can anybody help me please
 
Last edited:
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  • #2
Hi FARADAY JR! :smile:

(pleeease don't give different threads the same name! :redface:)
FARADAY JR said:
find the area bounded by :
4x+y^2=12
x=y

I'm lost how am i supposed to set them equal to each other if the second equation is y=x?

(where did √3x-12=0 come from? :confused:)

just replace y2 by x2 :wink:
 
  • #3
tiny-tim said:
Hi FARADAY JR! :smile:

(pleeease don't give different threads the same name! :redface:)


(where did √3x-12=0 come from? :confused:)

just replace y2 by x2 :wink:
Ok, So
4x+x^2-12=x
3x+x^2-12=0
3 (x+2)(x-2)=0 ?
 
  • #4
what do i do next?
 
  • #5
FARADAY JR said:
4x+x^2-12=x

nooo :redface: … where did that x on the RHS come from? :confused:
 
  • #6
tiny-tim said:
nooo :redface: … where did that x on the RHS come from? :confused:

I was trying to do f(x)-g(x)=0
so I can find the high and low
 
  • #7
so should I do it like this:
4x+x^2-12=0
(x+6)(x-2)=0
where X = 2,-6
?
 
  • #8
Yup! :biggrin:

(and now can you get the area? :wink:)
 

What is the concept of "finding the area between curves"?

The concept of "finding the area between curves" involves calculating the area enclosed by two curves on a graph. It is used to solve various mathematical and scientific problems, such as determining the volume of a solid or the work done by a force.

How do you find the area between two curves?

To find the area between two curves, you first need to identify the points of intersection between the two curves. Then, you can use integration to find the definite integral of the difference between the two curves over the interval between the points of intersection.

What are some real-life applications of finding the area between curves?

Finding the area between curves has many real-life applications, such as calculating the volume of irregularly shaped objects, determining the amount of paint needed to cover a curved surface, and estimating the work done by a force in physics.

What are the common challenges when finding the area between curves?

Some common challenges when finding the area between curves include accurately identifying the points of intersection, choosing the correct integration method, and handling complex curves or multiple curves within the same interval.

Are there any limitations to using "finding the area between curves" in problem-solving?

While "finding the area between curves" is a useful tool in problem-solving, it does have its limitations. It may not be applicable in certain situations where the curves are too complex or when the area is non-existent, such as with curves that do not intersect or when the area extends to infinity.

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