# Finding the area between curves

## Homework Statement

find the area bounded by :
4x+y^2=12
x=y

## The Attempt at a Solution

f(x)= √4x-12
g(X)= x
√4x-12=x
√3x-12=0

I'm lost how am i supposed to set them equal to each other if the second equation is y=x? can anybody help me please

Last edited:

tiny-tim
Homework Helper
Hi FARADAY JR! (pleeease don't give different threads the same name! )
find the area bounded by :
4x+y^2=12
x=y

I'm lost how am i supposed to set them equal to each other if the second equation is y=x?

(where did √3x-12=0 come from? )

just replace y2 by x2 Hi FARADAY JR! (pleeease don't give different threads the same name! )

(where did √3x-12=0 come from? )

just replace y2 by x2 Ok, So
4x+x^2-12=x
3x+x^2-12=0
3 (x+2)(x-2)=0 ?

what do i do next?

tiny-tim
Homework Helper
4x+x^2-12=x

nooo … where did that x on the RHS come from? nooo … where did that x on the RHS come from? I was trying to do f(x)-g(x)=0
so I can find the high and low

so should I do it like this:
4x+x^2-12=0
(x+6)(x-2)=0
where X = 2,-6
?

tiny-tim
Yup! (and now can you get the area? )