Finding the Area Between Two Curves: Graphical vs. Algebraic Methods

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The discussion focuses on finding the area between two curves defined by the equations y^2 = x and y = x - 2. The intersection points of these curves are determined to be (1, -1) and (4, 2). The integral setup for calculating the area is established as ∫ from y = -1 to y = 2 of the expression (y + 2 - y^2) dy, which represents the area between the rightmost curve and the leftmost curve. This method combines both graphical understanding and algebraic setup for area calculation.

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I know how to do this graphically, but I can't remember how to set it up the long way. The equations are:

y^2=x and y=x-2

I know it should be easy, but it's late and I can't think...
 
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stewe151 said:
I know how to do this graphically, but I can't remember how to set it up the long way. The equations are:

y^2=x and y=x-2

I know it should be easy, but it's late and I can't think...

Find the intersection points then set up the integral from the one intersection point to the other of the "larger" curve minus the "smaller" curve.
 
Solve for the points of intersection of the two curves:

[tex]x=y^2[/tex]

and [tex]y=x-2 \Rightarrow x=y+2[/tex]

the intersection of these curves occurs at the values of y such that

[tex]y^2=y+2 \Rightarrow y^2-y-2=(y+1)(y-2)=0[/tex]

so [tex]y=-1,2[/tex] and recall that [tex]x=y+2[/tex],

so the points are: (1,-1) & (4,2)

The integrand is easiest as: rightmost curve - leftmost curve = [tex](y+2) - y^2[/tex]

and the integral is then [tex]\int_{y=-1}^{2} (y+2-y^2)dy[/tex]
 

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