Finding the Area Inside Polar Equations

Click For Summary
SUMMARY

This discussion focuses on calculating the area enclosed by polar equations, specifically the lemniscate defined by r² = 4cos(2θ) and the six-petaled rose defined by r² = 2sin(3θ). The area can be determined using the formula A = ∫(1/2 r² dθ). The participants emphasize the necessity of graphing the Cartesian equivalents, y = 4cos(2x) and y = 2sin(3x), to identify the integration bounds effectively, as the textbook lacks relevant examples.

PREREQUISITES
  • Understanding of polar coordinates and equations
  • Familiarity with integration techniques in calculus
  • Knowledge of graphing functions in Cartesian coordinates
  • Experience with periodic functions and their properties
NEXT STEPS
  • Study the derivation of the area formula for polar curves
  • Learn how to graph polar equations using software tools like Desmos or GeoGebra
  • Explore the properties of lemniscates and rose curves in detail
  • Practice finding integration bounds for polar equations through various examples
USEFUL FOR

Students and educators in mathematics, particularly those focusing on calculus and polar coordinates, as well as anyone interested in advanced graphing techniques and area calculations in polar systems.

apphysicsgirl
Messages
9
Reaction score
0
1. Find the area of the region described:
a) inside one loop of the lemniscate r^2=4cos(2theta)
b) inside the six-petaled rose r^2=2sin(3theta)

2. A=integral [1/2 r^2 dtheta]
Are there any easy ways to determine the integration bounds? (without graphing)
Our textbook doesn't give any examples like this.
 
Physics news on Phys.org
I don't think there's an easy way that doesn't involve graphing something. For the first one, sketch a graph of y = 4cos(2x) and for the second one, sketch a graph of y = 2sin(3x).

These are not polar graphs, but they can give you some insight into what the corresponding polar graphs look like.

For y = 4cos(2x), the period is pi, so it's pretty easy to find an interval on the x-axis that corresponds to one loop of the polar curve. Note that you don't want any y values that are negative, since your polar curve involves r^2.
 

Similar threads

  • · Replies 19 ·
Replies
19
Views
2K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 3 ·
Replies
3
Views
2K
Replies
3
Views
1K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 3 ·
Replies
3
Views
3K
  • · Replies 13 ·
Replies
13
Views
2K
  • · Replies 10 ·
Replies
10
Views
3K
  • · Replies 7 ·
Replies
7
Views
2K
  • · Replies 2 ·
Replies
2
Views
1K