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## Homework Statement

Find the area under y = 6x

^{3}- 2 for 5 <_ x <_ 10

## Homework Equations

## The Attempt at a Solution

I'm not sure how it wants us to do it; do we use sigma notation or the general right/left-hand sums?

Using sigma notation, delta T = 10-5/n

T

_{0}= 5/n (?)

T

_{1}= 10/n

T

_{i}= 5i/n

5/n[tex]\sum6(5i/n)^3 -2[/tex]

750/n^4 -2 (Sigma) i^3

I'm not sure if I can bring the 2 out like that, and I'm also not sure what i^3 equals (is it (n(n+1)/2)^3?)

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